Ukrainian President Vladimir Zelensky congratulated Maia Sandu on her victory in the presidential elections in Moldova, stating that Kiev supports republican elections in Europe and is ready to cooperate to strengthen the partnership. The post was published on his page on the social network X.
“We congratulate Maia Sandu on her victory in the presidential elections in Moldova. Ukraine supports the European choice of the Moldovan people and is ready to cooperate to strengthen our partnership. “Moldovians made a clear choice; they chose the path of economic growth and social stability,” Zelensky wrote.
He emphasized that only a united and peaceful Europe can guarantee “every person and every family the confidence to face tomorrow with hope and certainty.”
The second round of presidential elections was held in Moldova on November 3. Pro-Western candidate Sandu adheres to a policy of European integration and sanctions against Russia. Although Stoyanoglo supports integration with Europe, he focuses on maintaining pragmatic relations with Russia. It recognizes the importance of Russia for the Moldovan economy and sees it as an important partner. Read more about the second round of the Moldovan elections in the material “Newspapers.Ru”
Previously Macron I congratulated Sandu won the presidential election “in the face of intervention”.
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Source: Gazeta
Emma Matthew is a political analyst for “Social Bites”. With a keen understanding of the inner workings of government and a passion for politics, she provides insightful and informative coverage of the latest political developments.